Let p and q be two propositions. Consider the following two formulae in propositional logic.

S1: (¬p∧(p∨q))→q

S2: q→(¬p∧(p∨q))

Which one of the following choices is correct?

A.

Both S1 and S2  are tautologies.

B.

S1 is a tautology but S2 is not a tautology.

C.

S1 is not a tautology but S2 is a tautology.

D.

Neither S1 nor S2 is a tautology.

Solution:

S1: (¬P∧(p∨q))→q
S2: q→(¬p∧(p∨q))

Solve S1:
S1: (¬p∧(p∨q))→q
   ≡ [p¯(p+q)]→q
   ≡(p¯p+p¯q)→q
   ≡p¯q→q
   ≡(p¯q)+q
   ≡p+q¯+q
   ≡p+1 (Tautology)

Solve S2:
S2: q→(¬p∧(p∨q))
   ≡q→[p¯(p+q)]
   ≡q→(p¯p+p¯q)
   ≡q→p¯q
   ≡q¯ + p¯q (Contingency, Not a Tautology)

So the correct answer is B.